Tried simplifying it of course, but didn't get far. Here's tbe problem:
''Express 3sin(3x)-4cos(3x) in the form Rcos(3x+\alpha),\alpha\ge0;R>0. Hence, find the smallest possible value of x for which 3sin(3x)-4cos(3x)=4.''
Bit confusing for me, especially the last part. How do you solve this, lads?
Ok, I had never seen a factorial problem like this, and the answer(n=7) didn't help me much in understand the solution either.
If (n+1)!/(n-1)! = 56 , what's the value of n?
Hello everyone, I was wondering if someone could solve this and explain it in detail. The answer is supposed to be a= -2. Let's cut to the chase:
If the two lines 2x + ay = 1 and ax + (a+4)y = 2 are parallel ,what is a?