Recent content by TheSerpent

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    3D Vectors Problem - Find Cross Product

    Homework Statement Given |\vec{a}| = 8, |\vec{b}| = 9 and the angle between vector \vec{a} and \vec{b} is 48° find the cross product, \vec{a} X \vec{b}. Homework Equations Let θ = angle between \vec{a} and \vec{b}. \vec{a} . \vec{b} = ( \vec{x}1 * \vec{x}2 ) + ( \vec{y}1 * \vec{y}2 ) + (...
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    Short Grade 12 Gravitational Problem

    The Question The Planet V has a year lasting 360 days. In the same star system is the Planet X. The Planet X has half the mass and triple the radius. A planet X year would be approximately _____ days The attempt at a solution Givens: Tv= 360days Tx= ? mv = mv mx = 1/2mv rv = rv rx = 3rvI...
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    How Does the Meteoroid's Acceleration Change as It Passes Planet Conniption?

    Forgot that Fg = -GMm / r^2 so that the - cancel out: F = ma a = F / m a = ( -Fg + Fe + Fb ) / m a = [-(-GMm/r^2) + (KQq/r^2) + (qvBsin90)]/m a = [-(-(6.67*10^-11)(5*10^25 kg)(10000 kg)/(20000000 m)^2) + ((9.0*10^9)(+10^6 C)(+5 C)/(20000000 m)^2) + ((+5 C)(10000 m/s)(0.001 T)(1))/(10000 kg)] a...
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    How Does the Meteoroid's Acceleration Change as It Passes Planet Conniption?

    mPerturbation = 10 tonnes = 10000 kg mConniption = 5 * 10^25 kg charge of Conniption [Q] = +10^6 C charge of Perturbation [q] = +5 C rConniption = 10500000 m altitude Perturbation = 9500000 m r = rCon + altitPert = 20000000 v Perturbation = 10000 m/s B Conniption = 0.001 T (perpendicular...
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    Grade 12 Gravitational Force Fields Questions.

    Thank you for your help! Can you also help us in our other post you commented on? We posted an idea but unsure!
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    How Does the Meteoroid's Acceleration Change as It Passes Planet Conniption?

    The forces that are involved in this question from what I can tell are gravitational and magnetic. Some possible relevant formulas are: Fg = GMm / r^2 Fe = kQq / r^2 Fb = qvBSin(theta) I think it would be required to substitute these into F = ma to solve for 'a' somehow, but I am not sure.
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    Grade 12 Gravitational Force Fields Questions.

    Find new velocity: K = mv^2 / 2 (9.973 * 10^9)+(9.97165 * 10^10) = (1000)v^2 / 2 v = √(2)(1.096895*10^11)/1000 v = 14811.44827 = 1.481 * 10^4 m/s This is the actual velocity so therefore the rocket will have sufficient velocity to escape.
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    Grade 12 Gravitational Force Fields Questions.

    Find orbital velocity: v = √(GM/r) v = √((6.67*10^-11)(5.98*10^24)/(13620000 + 6380000) v = 4.466 * 10^3 m/s Find orbital kinetic energy: K = mv^2/2 k = (1000)(4.466*10^3)^2/2 K = 9972578000 = 9.973 * 10^9 J Find escape velocity: v esc = √2 v v esc = √2 (4.466 * 10^3) v esc =...
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    Grade 12 Gravitational Force Fields Questions.

    So what's going to be changed in the calculation process (how do you find the new velocity?)
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    How Does the Meteoroid's Acceleration Change as It Passes Planet Conniption?

    1. The meteoroid Perturbation passes near the planet Conniption which has a mass of 5 * 10^25kg, a charge of +10^6 C and has a radius of 10500km. The meteoroid has a mass of 10 tonnes and a charge of +5 C. The meteoriod has an altitude of 9500km and a velocity of 10km/s. The planets magnetic...
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    Grade 12 Gravitational Force Fields Questions.

    [b]1.Nasa fires a 1 tonne space probe, from a stable orbit of altitude 13,620km using a giant rail gun. The rail gun provides the probe with 9.97165*10^10 J of additional kinetic energy. Determine if the probe has enough velocity to escape the Earth's gravity well. The Earth's mass and radius...
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