Recent content by The Divine Zephyr

A=60+(S+\Delta P) \times \frac{L_2}{L_1}

\begin{array}P=A(1+\frac{r}{100})^n \\ \sqrt[n]{\frac{P}{A}}=\frac{r+100}{100} \\ r=100\sqrt[n]{\frac{P}{A}}-100\end{array}

I need to know: In a closed system sealed off from outside air, if water from a mass of basic water evaporates, will the pH of the air be affected? If so, when the air condenses, how wil the pH of soil in the closed system be affected? Thanks for the help.

\textrm{pwnz0rz}= \frac {-1337 \textrm{search engine}\pm \sqrt{(1337 \textrm{search engine})^2-4(1)(\textrm{gmail})}}{2} Hmm, so you can mix words with numbers and pretty print in latex with \textrm. ...dont ask

If \sqrt{9+4\sqrt{5}}=\sqrt{a}+\sqrt{b}, find all ordered pairs (a,b) The equation looks hauntingly like a elliptic curve, so I tried that but it didnt really help. I tried just simplifing it, but it got really messy really fast. Can someone please help?

Though I am still alittle quesitonable about sqrt 2 as an answer, I think I understand the reason the answer is correct.

I idnt approximate. I got 2 for a stack of 3 sqrt twos, but as I did x^{x^{x^{x^{...}}}}, it went to infinity. \log_{x}2=x^{x^{x^{x^{...}}}} Can you show me how your solution was attained? I see the link, I'll go check it out.

I see where you are coming from, but I can't see it working the the equation... SQRT [2]^SQRT [2]^SQRT [2]=2, but as soon as more SQRT [2]s are stacked, it flies off the mark...

I'm sorry, the correct expression for me would have been 0<x<1 will converge to 1

It doesn't, \sqrt{2}^{\sqrt{2}^{\sqrt{2}}} does infact come very close to 2 (I think exactly, don't have my 89 with me...), however. But as soon as more terms are piled on, it spirals into infinity.

So far, I got that if x=1, my LHS=1 if 0<x<1, LHS converges to 1 if x>1, LHS diverges I plugged it in on a calculator and it divirged into infinity... Go for it, I'll think about that, too.

Infinite Exponent "towers" Please help me solve this problem; I don't even know how to start... Solve for x: x^{x^{x^{x^{...}}}}=2

\int \frac{3}{4+3x^2}dx=\frac{1}{2}\sqrt{3}\arctan(\frac{x\sqrt{3}}{2})+C

\int_{1}^{\sqrt[3]{3}}z^2dz \times \cos{\frac{3\pi}{9}}=\ln{\sqrt[3]{e}} Integral z squared dz from 1 to the cube root of 3 times the cosine of 3 pi over 9 equals the log of the cubes root of e Whoever thought that up was a really clever math poet ;)

Remember, if multiple events need to cooexist, multiply their probabilities together (similar to an "AND" gate in programming) and if either goes, add their probabilites (similar to "OR" gates)