Ok, I think I did what you said.
So with .252 voltage (that seems low compared to everything else I've read) from before and a measurement of 12.25 miliamps? (multimeter setting is 40m/10A). So R = V / I.
So .252/.01225 = 20.57. That doesn't seem right either.
Now I went back and tried to measure the resistance on different settings on the MMeter.
At 40M I got -9.67
At 4000K. -967
At 400K. -101.2. (??)
At 40K. -12.62
That's not just a shift in decimals that I was expecting, is it?
This is why I'm so confused.
You just helped me put together that I needed to measure BOTH resistance and voltage. Up till now I was just trying to measure voltage and not under standing the reading the MMeter was giving me. So if V =I*R then R = V/I. So .252/970 = .000259
Could you walk me through that process?
My father in laws multi meter is more complex than I'm used to.
The Ω quadrant on the dial has settings for
Continuity
4000M
40M
4000K
400k
40k
4k and
400 with the sound waves.
In fumbling around with it, I've plugged in the red LED...
Hello, my name is Mike, and I have just enough electrical engineering knowledge to be dangerous. This season I have inherited a programmable LED Christmas light set up from my father-in-law who is no longer with us to help guide me with his EEngeneering knowledge.
Here's the issue.
I have...