Recent content by tater08

  1. T

    Rolling Ball Height In Terms of Ho

    i do not know how to come about to solving this part (1) You need to find the final height in terms of the original height, not in terms of v. Hint: Since the only energy contributing to the final height is the translational energy the ball had at the bottom of the hill, compute that...
  2. T

    Rolling Ball Height In Terms of Ho

    The translational energy at the bottom of the hill would be 1/2 mv^2 and the moment of inertia for the hollow sphere is (2mr^2)/3 =I the height at the bottom of the hill is 0. I just can't figure out the final height in terms of the original height with the given information.
  3. T

    Rolling Ball Height In Terms of Ho

    If there is no friction, the disk going up the frictionless ramp will continue rotating at the same angular velocity the entire time it's on the ramp. Therefore when it gets to its maximum height on the ramp, the disk will still have a significant amount of its energy stored in the rotation of...
  4. T

    Rolling Ball Height In Terms of Ho

    well on the rough decline, the rotational energy is being turned into the translational energy which can be converted to potential gravitational energy while up the smooth incline, the only energy would be the rotational.
  5. T

    Rolling Ball Height In Terms of Ho

    the translational KE of the ball when it reaches the bottom is 0.5 mv^2 but the trip down and the trip up will have a difference due to gravity
  6. T

    Rolling Ball Height In Terms of Ho

    Homework Statement A basketball (which can be closely modeled as a hollow spherical shell) rolls down a mountainside into a valley and then up the opposite side, starting from rest at a height H0 above the bottom. In the figure, the rough part of the terrain prevents slipping while the...
  7. T

    Finding the Ratio of Electron to Proton Speed in Beta Decay

    Well the charge is conserved so wouldn't that leave the E=mc^2 equation. Once you get the energy, you can plug that value into the KE=0.5 mv^2 in order to get the velocity?
  8. T

    Finding the Ratio of Electron to Proton Speed in Beta Decay

    Homework Statement Beta decay is a radioactive decay in which a neutron in the nucleus of an atom breaks apart (decays) to form a proton and an electron. The electron is also known as a beta particle. The proton remains in the nucleus while the electron shoots out. Assuming that the...
  9. T

    Kinetic Energy Dissipation in a Colliding System

    I figured it out. 1-(KEf-KEi)/KEI is basically the equation to use.
  10. T

    Kinetic Energy Dissipation in a Colliding System

    (Kei-Kef)/ KEi = ((1-(m1/m1+m)) KEi)/KEI = M2/m1+M2 1/ (1+1) KE should be 0.5 or 50 percent. But this is the wrong answer And I'm Totally lost. thanks for any help that i may receive.
  11. T

    Kinetic Energy Dissipation in a Colliding System

    Homework Statement A hockey puck B rests on a smooth surface of ice and is struck by a second puck A , which was originally traveling at 40.0 m/s and which is deflected 30.0 degrees from its original direction. Puck B acquires a velocity at a 45.0 degree angle to the original direction of...
  12. T

    Calculating the Length of a Rough Patch Using the Work-Energy Principle

    Homework Statement On an essentially frictionless horizontal ice-skating rink, a skater moving at 3.00 m/s encounters a rough patch that reduces her speed by 45.0 % to a friction force that is 25.0 % of her weight. Use the work-energy principle to find the length of the rough patch...
  13. T

    Gravitation Force Between Two Massive Bodies

    the volume of a sphere is 4/3 pi (2.5)^3 if the nucleus radius is 5km across the radius is 2.5 km. after converting the 2.1 g/cm^3 to 0.21 kg/m^3. 0.21 kg/m^3 = M/65449.85 m^3 M=13744.47kg F= G (m1 *m2)/R^2 F= (6.674 * 10 ^-11) ((13742.4kg)(385kg))/237000m F=6.29* 10^-15is...
  14. T

    Gravitation Force Between Two Massive Bodies

    Homework Statement The Stardust spacecraft was designed to visit a comet and bring samples of its material back to the earth. The craft is 1.7 m across and has a mass of 385 kg. In January 2004, from a distance of 237 km, it took the photograph of the nucleus of comet Wild2, shown in the...
  15. T

    Kinetic Friction To Find Acceleration

    Thanks Rake, Perrilux and Lowly Pion. I ended up getting the right answer. Thanks.
Back
Top