Recent content by tanzerino

i got it .it will be EA=densityXv/epsilon then EX2*pi*r*h=densityXpi*r^2*h/epsilon then 2E=density*r/epsilon then E=density*r/2epsilon

i tried this rule and EA=densityXv/epsilon so E=Q/Aepsilon =Q/4pir^2Xepsilon ? doesn't give an answer

i don't understand how to do the triple integration however i remember that E=k int(dq/r^2) E.dA is phi i want E

[b]1. Charge of uniform density 76nC/m^3 is distributed throughout a hollow cylindrical region formed by two coaxial cylindrical surfaces of radii 1.5 mm and 3.7 mm. Determine the magnitude of the electric field at a point which is 2.6 mm from the symmetry axis. I tried...

1. The average translational kinetic energy of a nitrogen molecule at temperature is _____ check picture 2. 3. The Attempt at a Solution : since nitrogen is diatomic then it has 5 degrees of freedom and therefore the average kinetic energy wouldn't be 3/2kt it would...

similar post to this but simpler problem: https://www.physicsforums.com/showthread.php?t=392014&highlight=mixing+steam+ice

thanks for your help.i will check for any mistakes with the teacher this is cengage and the second mistake already.shame!

any help?

i get it now so we balanced them all into one 30kg mixture at 0 celcius and check the excess energy that will heat the mixture.the melting of ice consumed some heat but condensation of steam or the energy inside steam was much greater which provided extra energy but after condensation the steam...

Einternal=Q+W Q he said is given so +ve and work from the graph is -ve calculated work was much greateer that's why i think the answer is -ve then wen i tried the numbers i get -1.5 which isn't an answer

Any idea?

so Before (11.3 - 8.325)MJ is equalizing the whole system into water and this is the excess energy used in heating water what is the 5kg*100C*4186J/kg/C = 5.06MJ

Before (11.3 - 8.325)MJ + 5kg*100C*4186J/kg/C = 5.06MJ

i didnt quite understand the last step though

so your way gives 40.3 which is approximately one of the answers