It makes so much more sense now! I think I got it.
Heat required in phase change, ice at 0 °C to water at 0 °C:
Q = mLf
Q = (1x106 kg)(334x103 J/kg)
Q = 3.34x1011 J
Heat required in heating water at 0 °C to 1x10-20 °C:
Q = mcΔT
Q = (1x106 kg)(4190 J/kg*K)(1x10-20 °C - 0 °C)
Q = 4.19x10-11 J...
Homework Statement
A 1x106 kg piece of ice is placed into a lake. How much heat is taken from the lake to raise the temperature of the ice from 0 °C to 1x10-20 °C? How much volume does the lake increase by?
Latent heat for water is 334x103 J/kg
Homework Equations
Found in my textbook,
cice =...