Well, knowing that the bottom area is the same for both, the volume contained in the left beaker would be A2h. Whereas, for the right flask, that would be...Ah + 1/2 Ah = 3/2 Ah. W,l = 2Ah vs. W,r = 3/2 Ah, so W,l / W,r = 4/3 again? I could be making a mistake assuming that the top, skinny part...
Homework Statement
Two open-top containers, #1 on the left
and #2 on the right, with equal base area A
are placed on two scales. The #2 container
on the right has an lower diameter twice that
of its upper diameter and the height of its
lower (larger) diameter is half that of its water
height...
Unfortunately, the answer is indeed Av(rho) (1/2 v2 + gh), but the problems in our database are often worded questionably. Thanks so much for your help!
I think I see what you're saying... are you reading the problem as stating that the acceleration is the result of a power applied after the fluid has been lifted through whatever distance? As though the liquid was lifted, and after that the power in question was applied? I had assumed it was a...
If only the end point matters, I guess that would mean the work done is (1/2 \rhov2 + \rhogh), multiplied by the change in volume = Av. That would be Av\rho(1/2 v2 + gh). I'm going to feel a little silly if that's the answer-- it is, after all, the one with a form that suggests an increase in...
Homework Statement
A pump lifts a liquid of density \rho to a height h and accelerates it from rest to a final velocity v.
What power P does the pump deliver to the liquid, if the liquid is being pumped through
a pipe with a cross sectional area A?
1. Av\rho + \rhogh
2. Not enough...
Homework Statement
Two traveling transverse waves propagate
down two long ropes under the conditions
that the linear mass density, tension, and
transverse displacement amplitude for the two
ropes are the same, but that one rope has
twice the length of the other.
If the shorter rope has a...