If the wave function was ##e^{ikz}## and if I injected this in the schrödinger equation, yes I will obtain this result. But the wavefunction is ##e^{ikz}e^{im\phi}f(\rho)## and if I write the eigenvalue equation of the Hamiltonian I will not obtain this, so I don't understand why we can say...
Hi, everyone.
Please check the following questions (extracted of the cohen Tanpoudji)
for the first question, here my Hamiltonian operator.
It's easy to see that it commutes with Lz and Pz.
Now we can determine a common eigenvector basis for these 3 operators.
For the angular part we need to...