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    MHB Find vertex, focus, and directrix of parabola: y^2+12y+16x+68=0

    Find the vertex, focus, and directrix of the following parabola: y^2+12y+16x+68=0 The form we have been using is (y-k)^2=4p(x-h) Any explanation would help too, I'm really stuck on this one. Thank you!
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