Hi @BvU
Thanks for the help :)
Whilst working on it over the weekend I have used the product of volumetric flow rate and density for now (thank you!)
In the textbooks, it says that the relationship between mass and volumetric flow rates for a compressible fluid is more complex than that for a...
I have converted given pressures from bar gauge to bar abs
Inlet pressure = 20 - 1.013 = 21.013 bar abs
Outlet pressure = 6 + 1.013 = 7.013 bar abs
therefore pressure drop (x)
x = {p_1 -p_2 \over p_1 } = {21.013 - 7.013 \over 21.013} = 0.6662542236 bar abs
Comparing to the chart values for...