does it then mean that this question is not doable?
the original question is they gave the length AB as 2sqrt(3) + 1
and the area as 5.5 cm square, and was asked to find AC, expressing it in some integer b sqrt(3).
So since L can be anything , i assume this question cannot be done?
yea i thought about pythagoras too, but how do i find L? the question only states the length of AB and the area. then it asks to find length of AC which is x in this case. i need to get rid of L somehow.
How should i approach it?
I have tried area formulas 1/2baseheight, 1/2absinc, sin law, cos law, and they all seem to just cancel each other out when i try to substitute them into solve the equations.
ok let's assume the triangle looks like this and i simplified the values. Given AB = 4 and we found the height through area formula to be 3. I am trying to get length of DB i.e. (L) through similar triangles ratio and then solve for x through pythagoras theorem AD,CD,x. Problem is, when I tried...
ok let's assume the triangle looks like this and i simplified the values. Given AB = 4 and we found the height through area formula to be 3. I am trying to get length of DB i.e. (L) through similar triangles ratio and then solve for x through pythagoras theorem AD,CD,x. Problem is, when I tried...
How should i approach?
I tried to replace sin(a) in 1/2absinc with sin rule, trigo, area half base and they all just cancel each other out.
Area formula 1/2 ab sin(c) => 5.5 = ½ (2√3 + 1)(AC) sin(a)
Area formula half base height => ½ (2√3 + 1) h = 5.5
h = 11 / (2√3 + 1)
sin(a) = h / AC...
I mean is it solvable?
it feels like something is missing? given only 1 length and the area, is it possible to find the other length without any special properties of the triangle like isoceles, equilateral etc?
i tried 1/2 base height, 1/2 ab sin(c), sin rule, cos rule
it is just a generic...
it feels like something is missing? given only 1 length and the area, is it possible to find the other length without any special properties of the triangle like isoceles, equilateral etc?
i tried 1/2 base height, 1/2 ab sin(c), sin rule, cos rule
it is just a generic normal triangle.
yea, but it feels like something is missing? given only 1 length and the area, is it possible to find the other length without any special properties of the triangle like isoceles, equilateral etc?
i tried 1/2 base height, 1/2 ab sin(c), sin rule, cos rule
Given a triangle ABC, whose area is 5.5 cm square, and length of AB = 2√3 + 1 cm, find the value of length AC.
Given triangle has no special properties like isoceles etc.
Only 1 length and area of the triangle are given. Is it possible to solve such a question? thanks.