im sure he would like it if is 80's pixelated images were hd'd the **** out, you know u would like it too...the only problem with the new cosmos i predict is that i don't believe neil will be able to as presentable as carl and as his uniquely divine knowledge and structure of explaining the...
I am not sure i quite understand what you mean by when you say
"Instead of solving for x in terms of y and z, and then y in terms of x and z, and then z in terms of x and y, just solve for x in terms of y and z, and leave y and z and parameters".
I thought that's what i did above, but of...
thanks for the lengthy response, I understood that first question after mark explained it, but now having troubles with the second one:
2x - 7y +3z = 11
how would I find x or y if I am always going to have 2 variables that I won't be able to find?
Ok, I already have come across a small issue for this problem:
http://img694.imageshack.us/img694/5315/m0a5.png
The issue with this problem is that in the solution they are asking for "s" and "t" which I am guessing are substitutes for either x,y or z. Now when I break down the equation I get...
Anyone seen the series Cosmos with Carl Sagan, just finished all of it, what a mind bending experience! Good stuff all the way! Neil degrasse tyson is coming out with a show called cosmos in 2013, perhaps in updated version of the old school show.
Homework Statement
Here is the problem:
http://img801.imageshack.us/img801/6770/oaza.png
Homework Equations
None really, just gauss jordon elimination I assume unless I am missing out on something
The Attempt at a Solution
First I multiplied the first row by -5 then added...
ok i got this far :
a = -1 -b
b = 3 -c
c = -1 -d
d = -5 -a
a being x1 b being x2 and so forth...just not sure what to do from this point on. If I plug one of the values into another they just cancel out each other, was I supposed to use gauss-Jordan elimination even further?
ok thanks for that, i got the solution! -.8926990813x^2 + 18.5x ... now i really need help with the linear problem, please with a cherry on top with chocolate whipped cream.
for the first question I did something like this (I have lots of notes scribbles, many attempts, easier to say what I did rather than write stuff out here, since it is much harder):
perim=x+2*h+Pi*x=37 => h=(37-x-Pi*x)/2
A(x)=h*x+Pi*x^2=(37-x-Pi*x)*x+Pi*x^2=37x-x*x
for the systems I just...
Ok I edited the first one and added a(x)= ? ... that's all the information I have on that question, and for the second one its hard to describe since I can't add a picture:
its formatted as such:
x1 + x2 = -1
x2 + x3 = 3
x3 + x4 = -1
x1 + x4 = -5
then there is 3 groups in a square bracket...