Recent content by sdfsfasdfasf

The joys of chemistry.

It's just strange because my textbook (from which this exam question is based off) claims that hydrated Fe3+ is yellow, and all other exam questions on this topic use that piece of information, its just this one that says its brown.

Wonderful, thank you so much, Orodruin.

I've been tasked with writing an equation to show the reaction of the Fe2+ complex with Cl2. I believe that the oxidation state of the Iron has changed, so I would write 2Fe(H2O)(6)^2+ + Cl2 -> 2Cl- + 2Fe(H20)(6)^3+, but I can't be sure this is correct. Is the 2Fe(H20)(6)^3 ion not yellow in...

So the resultant (centripetal) force varies, correct? As the velocity's magnitude varies throughout the loop.

So far I believe that speed changes during vertical circular motion, and its very hard to get uniform circular motion that is in the vertical plane. This is because there is a difference in vertical height between the bottom/top of the circle so at the top the object must have done work against...

Silly me, if the force is at the center then the distance is 0 and it provided no moment.

If there is a force counteracting the force T, does that not provide an opposite moment to the force T? Then why is the moment provided by T not half of the calculated value of 40?

The question is regarding this image, I understand the two 50N forces provide a clockwise moment of 40 x 10^-2 x 100 which gives option D, as this moment must be balanced by the moment given by T. Now my question is, how is the net force on this system equal to 0? It says it is in equilibrium...

This is taken straight from an A-Level Physics Examination which is the highest level of examination in the UK you can take before university. :mad:

I suppose they have assumed that the handle is vertically above the wheel? Such that the line of action of the vertical component goes through the wheel itself and therefore doesn't provide any moment?

This is the markscheme provided, does it provide any insight as to what the author has done?

I am stuck on part b) i). I understand that there is no normal force from the ground as the bin is on the point of being lifted off the ground, that is all fine. That leaves R, F and W. I know W is 40g, and I am required to calculate F, therefore it makes most sense to take moments about the...

This thread did well, I am happy.

It is still under the main topic question "What actually is a particular solution?".