erm for the first inequality w(s) would be given by xr(s) - xl(s)? so it would be (b-d)s/λh + h - ds/h - h = (b-d)s/h - ds/h. this would be a dimension of width as the h and λh would cancel with the s to leave b-d and d?
thank you both for your replies, yes your right i copied it up wrong i meant to put (b-d)
how do you man some legnth is missing? a h canceled when calculating w(s). that's fine i was just unsure about the integration but i think that may help thanks again
Homework Statement
im required to find the width of the strip of integration across the triangular lamina w(s) and then integrate to find the area
I am given w(s) = x_right(s) - x_left(s) between 0<s<λh and λh<s<h
Homework Equations
The Attempt at a Solution
i have...
i have this example of a hydrostatic force on a plane surface.
what i don't understand is how the width of the integral strip is derived
it says w(s)=b(s-s1)/L i don't understand how this comes about?
would be really greatful if anyone could direct me i can't find anything on...
just looked at your working how did you now that the compound cylinder was made up of the same material, is that from the one value of young's modulus? also did you work out the stress produced from the shrink fit not just the internal pressure?