Homework Statement
We have a town we three papers.
Paper 1 is read by 64 % of pop.
Paper 2 is read by 46 % of pop.
Paper 3 is read by 54% of pop.
3% read both Paper 1 and Paper 2.
8% read both Paper 1 and Paper 3.
12 % read Paper 2 and Paper 3.
5% read all three...
thank and then I should be able to arrive at the solution ?
But if I solve the rewritten equation with respect to z I get z=-b^2*t^2/(t^2-p^2)?
I am no closer to y = b/(sqrt(p/t +1) * sqrt(p/t-1)) which is suppose to be the solution for original equation.
Which is still no closer to y =...
Thats easy a/b - c/d = ad/bd - bc/bd = (ad-bc)/bd
But regarding the other expression I attempted now 10 times if I take my equation
X(y) = y/(t*(sqrt(b^2+y^2)) - 1/p = 0
and use the commen denominator (p*t(b^2+y^2))
I end up with the expression:
py/(pt*sqrt(b^2+y^2)) -...
Okay, Glad I am not totally stupid then :)
So any if I take the original equation : y/(t*(sqrt(b^2+y^2)) - 1/p
and use the commen denominator p*t*sqrt(b^2+y^2)
I arrive at
py/(p*t*sqrt(b^2+y^2) - (t*sqrt(b^2+y^2)/(p*t*sqrt(b^2+y^2) =
y/(t*sqrt(b^2+y^2)) - 1 = 0 ?
But if...
I get that now but the only commen denominator I can deduce is my pee size brain is :)
p*t*(b^2+y^2))
But what I get from what you are saying is that denominator is wrong?
So I am lost here :( What would you surgest I do as a first step with original equation? I can add 1/p on both sides I see that and next add the denominator on both sides. But what next?
Thank you for your answer.
That implies that I need to solve the equation
(y*p - t*p*(sqrt(y^2+b^2)) = 0
Which allows me to arrive at the solution (using my graphical calculator)
y = -b * p *(sqrt(-1/(p^2-1)
But solution is suppose to be:
y = b/(sqrt(p/t +1) * sqrt(p/t-1))...
Homework Statement
Given the following equation
X(y) = y/(t*(sqrt(b^2+y^2)) - 1/p
How would I go solving that equation X(y) = 0 with respect to y?
The Attempt at a Solution
I can choose a commen dominator called p*t*(b^2+y^2)
But I when end up with
((y*p -...