Recent content by samieee

@dark_elf, You should not ask for solution of this question. It's a breach of honor code you accepted at 8.01x course.

I have seen both types of phasor diagram in different books. But the first one is the accurate answer, I think. Because of Lenze's law.

Yes, amplitudes of all the waves are same.

So, from the comparison, I see that square wave has the higher value than any other rotating wave. DC shifted square wave has even higher value as it should have.

Reading the wiki page may give you some information, http://en.wikipedia.org/wiki/S_plane

Suppose there are some waveforms to be used as current input: i)sine wave ii)square wave iii) triangle wave iv)sawtooth wave and v)sawtooth wave with both the cycles(+ve half cycle and -ve half cycle) in positive Y axis. Which wave will generate more heat? Actually, I faced this question in a...

Yeah, in case of dc generator the ac emf is induced and ac current flows through the coil which is rectified by commutator and the terminal end we get the dc voltage as electrical energy. But in dc motor we already give dc supply in the input terminal, where does the rectification happen?

Actually this not a question, I want to justify whether my concept is right or wrong. So let's start. Faraday's law of electromagnetic induction e=Nd\varphi/dt explains the way of electromagnetic energy conversions. The induced voltage is always ac because the rate of change of flux is...

If you want to do a circuit simulation you have to start from capture student>file>New>project.

We all know the coulomb's law of electrical force between two charges q_1,q_2 equals to \normalsize F= Kq_1q_2/d^2. But this law is not precisely true when the two charges are moving. We know for a single charge q moving with a velocity v the force is \ F=q(E+v×B) What is the straightforward...

For a no load ideal transformer V1 is anti phase with E1? or in phase like this?

watch this lecture http://www.youtube.com/watch?v=NkRk_xaRwjg&feature=relmfu and following 4-5 lectures. You will have clear cut transformer concepts.

Thanks to all folks for helping me understand the concept. For the last two days I was busy with it, studied from several sources. Now I have managed to solve my confusion.

According to boylestad's "Introductory Circuit Analysis", chap-10(capacitors) section 10.3: http://books.google.com.bd/books?id=cH0KitWACEcC&pg=PA274&dq=boylestad+eleventh+edition&hl=en&sa=X&ei=wBx2T9uLOcrKrAfWiqWLDQ&redir_esc=y#v=onepage&q&f=truepage 398 Those are the words that made me...

But before that? Isnt it open in all conditions due to the dielectric between the plates?