So I would do mgh, for the GPE and then solve to work out v from 1/2mv^2 ? I'm guessing you take the height in regards to a triangle? Find the resultant vector or rather the hypotenuse?
If so I think I understand.
Thanks for the help.
So If I work out I = (1/12)*M*R2
Then τ = MG* 10x10-2 (as the length of the rod is 20x10-2 - Only weight is
acting)
Then I use the solution to that and plug it into (1/2)ω2*I and solve for ω?
So to ask simply, apologies if I'm wrong. As we know that both waves have the same amplitude and their resultant is 25% greater, could I draw a line joined to another line which as at an angle. Label the angle outside of the two lines (apex) as theta. After this I could use Pythagoras to...
A uniform rod of mass M=5.0 kg and length ℓ=20 cm is pivoted on a frictionless hinge at the end
of it. The rod is held horizontally and then released.
a) Use the parallel-axis theorem to determine the moment of inertia of the rod about the hinge (ie
its end).
b) Determine the angular...
So like.. e^i(wt-kx) ? I never really understood this method so I should probably look it up, how would you apply that to this question? If I may ask
Thanks for the help!
Two waves are identical apart from a phase difference, they create a resultant wave of 25% increase of the original amplitude, what is the phase difference.
sin(alpha)+sin(beta)=2sin(1/2)(alpha+beta)cos(1/2)(alpha-beta)
Asin(kx+wt)=2sin(1/2)(alpha+beta)cos(1/2)alpha-beta)...