Well...I tried it and for the first equation I realize that I don't have the maximal height since I don't have the height of the building. And the second one seems..unsolvable.
There is a lot of equations involivng the angle, I could pick the one with the maximum height that says:
H= (initial velocity^2*sin(alpha)^2)/2*g
Or tan(alpha) = Vo*sin(alpha)/Vo*cos(alpha)
Vertical velocity= -g*t+ maximum height ?
or (y(x)-L-(0.5*g*t^2))/t=Vertical velocity
(To be honest, I think I'm lost. I see your point but there is so many equations I don't know which one I should use.)
Because of the total height of the building that I don't have, I don't think I can.
If I "cut" the motion to the top of the building to a point on the motion in the same horizontal, Delta x still missing even if I have Delta y which is the 20meters.
Homework Statement
A ball is thrown at the edge of the roof of a building in a direction at an "alpha" angle above the horizontal. It landed 5 seconds later at 50 meters from the building. The maximum height reached by the ball during its trajectory is 20 meters above the roof.
Find The...