Or should it be this,
= DQ = DT/ (L1/k1A + L2/k2A) where L = length of the rod. A = cross sectional area of rod.
i had,
DQ = DT / (1/k1A + 1/k2A)
Is it dependent on the length?
I just need the equation, i am not going to derive everything from first principles, you can see what i have done,
Dt / sum of R where, R is as stated.
I am not William Thomson attempting to experimentally derive with this conclusion, i just have asked for a verification of the above...
Homework Statement
Hello, first question here,
A copper rod and an aluminium rod are in thermal equilibrium with each other. Copper rod = 50cm long and the aluminium rod is 20cm. Radius of pair is 8cm.
Copper end is heated (and maintained) at 80C , other end of pairing is 20C. k of...