The op specified 10 -100 kw. We don’t know long it can fall as we don’t know the height. Yes we are limited by physics but we are not limited by existing techniques if we are open to ideas. Read any post in this forum that questions existing ideas or has a different approach and you’ll see the...
Small turbines are plagued by issues caused by boundary layers. As they are caused by surface area small diameters have a larger boundary layer ratio than large diameter. With a homemade jet engine using a turbo the turbine has to produce 105 hp to drive the compressor fast enough to cause...
Typical of this forum. Everyone projects their own limits onto others thoughts.
Your idea is good and can be worked. You’ll need an external energy source to lift your weight though. Even lifting a smaller weight as your 500kg falls will decrease the power available to be generated. The option...
Joules and watts are per second and are equal to 1 Newton metre. This is my original question as the units confused me. Maximum torque in a turbine is caused by deflection and therefore maximum torque is at stall where the blade rotation doesn’t lessen the deflection pressure. If the blade is...
Watts are watts per second also so they are the same.
The pelton turbine is an impulse turbine and uses different properties of flow than a gas turbine. All gas turbines generate maximum torque at stall as that is where the maximum gas deflection is occurring. At rotational speed the gas...
Watts is equal to Newton and as the mass flow rate and velocity is calculated as per second that final answer of 163 watts ( newtons ) is divided by 1 so the answer remains 163. Am I missing something.
Yes that half mass times velocity squared is half of the flow rate of 0.00129kg per second ( so that is 0.000645 kg per second ) multiplied by 503 metres per second squared. Looking for a max torque at stall so there is no angular momentum. As with all turbines max torque is at stall and power...
Pressure drop is from 7333 pascal to 867 pascal with a fluid density of 0.051 kg per cubic metre passing through a tube ( no restriction in diameter as in a nozzle ) with a diameter of 8 mm.
I have a nozzle through which a water vapour passes at 503 metres per second with a density of 0.051 kg per cubic metre giving a mass flow rate of 0.00129 kg per second. Using half mass times velocity squared I have an answer of 163. Is that answer 163 newtons and if it is how do I convert to...
Both sides are sealed at sea level atmosphere (14.7psi ). I’m measuring vacuum created. So the starting pressure is 1 atm and the finish pressure is 40 inches h20 on both sides