Homework Statement
A sample is put in tension and a strain rosette gives the following results:
i) Calculate principal strains and poissons ratio using Mohrs strain circle.
ii) Calculate principal stresses from principal strains and poissons ratio.
Homework Equations
Mohr's strain circle
γ =...
Homework Statement
Homework Equations
Trigonometry equations, p=m/v, A = pi * d^2 / 4
The Attempt at a Solution
i) mass calculated is 9.318kg at 150° from A
ii) diameter = 0.235m
I apologize for the messy working, I am just wondering if I have followed the correct procedure or not...
Homework Statement
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I can't seem to get the image links to work sorry! Also, I think the question is supposed to say 2.5mm radius notch, not 10mm
https://imgur.com/Klxw4gG
https://imgur.com/C9d81Rl
https://imgur.com/7H421ou
Homework Equations
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q = Ka - 1 / Kt - 1
M = Fd
(σa / σ'e)...
Homework Statement
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problem - https://imgur.com/34yTyCAHomework Equations
I = d . b^3 / 12
tmax = (F / I . b) . (A1 . y1) + (A2 . y2)The Attempt at a Solution
It is asking for the maximum shear FORCE in the beam. Do I take the maximum value from the shear force diagram as shown in my...
Homework Statement
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problem - https://imgur.com/SKeTUXNHomework Equations
Mohrs circle
The Attempt at a Solution
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I have drawn 2 induced loading elements (shown at the bottom of of my working) I just seem to have conflicting information from some class examples and am wondering...
Homework Statement
Mohrs circle question - https://imgur.com/SKeTUXN
Shear stress in I beam question - https://imgur.com/34yTyCAHomework Equations
Mohrs Circle - None
Shear stress in I beam - I = d . b^3 / 12
tmax = (F / I . b) . (A1 . y1) + (A2 . y2)The Attempt at a Solution
For the...
Great, thanks so much for the help. Got there in the end hahah. The doubled value probably comes from the fact the pins are under double shear, 2 pins with 2 shear points each puts the shear value for the pins at force = stress * 4 * Area. That's how I interpreted it anyway, It still comes in at...
Right, I should say force = stress * area.
When I calculated P around the maximum force that can be applied to the brass (4.8MN) and steel pins (814.3kN) I got P as 13.8MN and 1.25MN respectively, which by this point the steel rod will have failed.
So to clarify, am I going down the right...
Seeing as the metal rod has a yield stress of 640MPa, I used stress = force / area to find the the amount of force before yield which is 201kN? I used the formula on the other components as well as since the steel rod yeilded at the lowest force I thought I should start there.. I am not sure...
Right, so I take moments about the 201.06kN force and find the reactive force at the brass block is 107kN which sums to P being 308kN. Does this seem correct? Am I right in taking the maximum force of the steel rod (201.06kN) as my left reactive force as this will fail before the pins? (814.3kN)...
Thanks for the response, I understand what you're saying, will the force P be distributed between the pins / rods and block up to 201kN? I'm just trying to figure out a solid value to work from. Am I to multiply the force at the pin by 0.8 for the moment to the left of P? I'm still confused as...
Homework Statement
See attached photo
Homework Equations
Stress = F/A
Area = pi d^3 / 4
Sum F h = 0, Sum F v = 0, Sum M = 0
The Attempt at a Solution
Hey everyone, after reading the question a number of times and not knowing for certain where to start, I figured because the stress and area...