I want the coefficients to be in basis B, not E. So I guess the solution provided above does that, since inputting [1 0 0]' (using B basis, this is u) gives me back [0 2 0] (which is 2v in B basis).
The question was: "Find the matrix D in the B coordinate system". Unfortunately it does not...
I don't know exactly what you are referring to when you say component, but here is what I meant:
The output from my original(incorrect) matrix was the B vectors in the standard basis.
So to get the output of [4 10 0]' (2v in standard), I would need to multiply B*D*inverse(b) by the vector u...
Aha! Thank you very much, that makes much more sense than what I was doing. The output should be what mine was in standard, not B!
Thank you very much.
@jbunii - Since v is in basis B, I just doubled v to get 2v. Does that make sense?
@LaneDance - When you multiply D times [1 0 0] (only as a vector) you get the first column of D, which I thought was 2v. So it does if I'm correct about 2v..
Hi all,
So this question is fairly basic, but I want to be certain I have the right idea before I do the other parts (asks about it in standard basis etc). It's a book question:
Homework Statement
Here are the vectors : u=[ 1 2 0] v=[2 5 0] w=[1 1 1]
This forms a basis B of R3...