Somehow, I was under the impression that we were discussing detectors, measurements, PDF's and delta distributions over the last several posts.
In that case, if your point was only that one can Fourier transform a delta distribution when appropriate and that complex exponentials are relevant...
With regard to #6, I was hoping to use an already published formulation, but if there is none, then I'll just derive it.
I am still very interested to see an explicit mathematical formulation of your approach regarding the delta distribution and measurement. I provided a mathematical...
Though I may disagree with the assumption of infinite measurement accuracy, the standard statistical approach the I utilize is fully capable of modeling such an assumption.
In statistics, there is more to a measurement than the measured value. There is also the variance. Based on the variance...
The larger goal is to consider the symmetries of Lagrangian densities in both X and K. Certainly, that does include elements of QFT, but it also includes the symmetries of basis transformations in both X and K, which is why I raised the question in this forum. My goal is to see if formulations...
In general, statistical theories do not formulate observations or measurements as delta functions. Why such a formulation is necessary or even proper in quantum theory is unclear to me.
First of all, the assumption that any particular observation (or eigenstate) should be represented by a delta...
From Auletta, Gennaro, Mauro Fortunato, and Giorgio Parisi. Quantum mechanics. Cambridge University Press, 2009. See section 2.2.5 Momentum representation, equation 2.148:
$$\hat{p} \tilde{\psi}(p) = p \tilde{\psi}(p)$$
(The same formulation can be found in Fitzpatrick, Richard. Quantum...
Thank you for your response.
Why do you assume that ##\textbf{p} \in K## is a point relative to the origin, let alone one represented by a delta function? I have made neither of those assumptions. A vector may or may not include the origin as one of its endpoints. If I wanted to represent a...
For ##\hbar =1##, the choice of K space or P space is a matter of convention. I also choose to use the Fourier transform convention ##e^{2 \pi i k x}## instead of ##e^{i p x}##. I tried to be explicit about all this.
I apologize, but I don't know what you mean in saying my calculation is...
How is the mapping ##m## part of the Fourier conjugate relationship? It does not respect the Fourier conjugate relationship between the spaces X and K. This is trivial to demonstrate.
Assuming ##\hbar =1 \rightarrow \textbf{p} = \textbf{k} = \{ k_0, \vec{k} \}##, where ##\vec{k} = \vec{p}##...
I am considering K space as the Fourier conjugate space of X space, not a completely independent space, and I am requiring that dynamics in K space respect that Fourier conjugate relationship between X and K spaces.
My opinion is that this exercise is both trivial and useful, and I want to see...
What I really want is the Poincare-type group in K-space, which of course is trivial to construct from the Lorentz group in K-space.
The article you quote is interesting but suffers from the following problem:
Given a 4-momentum ##\textbf{p} \in K##:
$$\textbf{p} = \{E_0,p_1,p_2,p_3 \} =...
My reference is: Schwichtenberg, Jakob. Physics from symmetry. Springer, 2018.
In this text, matrices are utilized for the generators of the Poincare group and these matrices are 4x4 or 2x2.
In any case, the generators, particularly the boosts, are related to complex rotations over an angle...
Can someone share a paper or chapter from a textbook if they know a good one?
I'm curious to see the explicit form of these matrices. In position space, the generators of boosts act on the rapidity, which can be related to velocity in X. Assuming the generators of boosts in K act on rapidity in...
It’s not the convolution theorem in that only $$\hat{f}_2$$ is Fourier transformed.
I was told by that $$\hat{f}_1$$ cannot be moved into the integral $$\int_{-\infty}^{+\infty} dx$$ and so the equation is not accurate. I disagreed and so posted the question. It seems an identity to me too.
I was wondering if the following is true and if not, why?
$$
\begin{split}
\hat{f}_1(\vec{k}) \hat{f}_2(\vec{k}) &= \hat{f}_1(\vec{k}) \int_{\mathbb{R}^n} f_2(\vec{x}) e^{-2 \pi i \vec{k} \cdot \vec{x}} d\vec{x}
\\
&= \int_{\mathbb{R}^n} \hat{f}_1(\vec{k}) f_2(\vec{x})...