Yes that's right. I'd fix it but I can't seem to edit it anymore. The correct integral should have an extra ##\frac{1}{r'}## factor in it, but I am still not sure what is the upper bound of integral so that it come out to be a constant.
I am having problem with part (b) finding the vector potential. More specifically when writing out the volume integral,
$$A = \frac{\mu_0}{4\pi r}\frac{dq}{dt}\int_{0}^{2\pi}\int_{0}^{\pi}\int_{0}^{?}\frac{1}{4\pi r'^2} r'^2sin\theta dr'd\theta d\phi$$
How do I integrate ##r'##?
The solution...
For reference, this is from Griffiths, introduction to quantum mechanics electrodynamics, p253-255
When deriving the ideal magnetic dipole field strength, if we put the moment m at origin and make it parallel to the z-axis,
the book went from the vector potential A
$$
A=...