Recent content by Ramjam

My intercept was 0.574 and my gradient 0.114, which comes out as 8.9 ish for resistance. this could be caused due to a rounding error, I am going to check my working and see if i can get the resistance closer to 8. Thanks for your help on this matter.

It can't be that easy thought surly, i know ohms law but surly i would have to work it out using the line of best fit? or it would seem pointless for me to calculate it?

I havent, when you say 8 how did you get that?

< Mentor Note -- thread moved to HH from the technical math forums, so no HH Template is shown > Hi everyone, Got a stats question here from my revision material, but I am not sure if I've answered the whole question or not...

It was 2am in the uk and after a long working day which i also do along side my course probably wasn't the best idea. Right here are my working so far now that I've been had some sleep, we start with I=12.5(1-e-t/cr) I then divide both sides by 12.5 removing the 12.5 from the right hand side...

in that case i don't under what you mean by

opps sorry that should be -i/12.5-1=e-t/cr

Heres the full question that i should of probably started with (my mistake) The current, i, flowing in a capacitor at time, t, is given by i = 12.5(1-e-t/cr where resistance, R, is 30KΩ and capacitance, C, is 20μF Determine the time for the current to reach 10 amperes? So i know that by...

The original equation was i = 12.5(1-e-t/cr the reason it became i over 12.5 was because i divided 12.5 on both sides to remove it from the right.

- l/12.5-1=e-t/cr However doesn't this cause another issue with now there's a negative on the left preventing me logging?

- l/12.5 -1 ?

By multiplying -1 to let's say -1 you get 1, therefore I can see that by multiplying -1 to my equation will result in the right hand side becoming e-t/cr However if i was then to multiply the other side as required i don't see what i will get?

Well I've been trying things for the past half hour with no luck, I am not seeing how i can multiply both sides to remove the minus from the "e"

Umm... I am not actually to sure? :/

Okay so adding -1 to both sides i/12.5 -1 = 1-e-t/cr -1 which when becomes i/12.5 -1 = -e-t/cr isnt the minus infront the the "e" become an issue? as you can log "-e" Thankyou for your help on the matter