d^2phi/dx^2= -2AB^2tanh(Bx), correct?
Now I have gotten the equation
tanh(Bx)[2AB^2-A+A^3tanh^2(Bx)]=0
I set 2AB^2-A+A^3tanh^2(Bx)=0
tanh(Bx)= sqrt[2B-1]/A
But now what? Was I supposed to change the tanh^2(Bx) into 1-sech^2(Bx)?
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