I have tried fixing that latex mistake But i can't find it. I have written it out and posted in #15, this time a bit more clearer.
Using that
$$d\theta=vdt/l$$
$$d\theta/dt=v/l$$
Thanks, I will verify the answer tommorow from our teacher
So a will be really small, making an angle slightly less than 90, to not change the magnitude
Exact angle would require the angle between ## \vec V ## and ##\vec V'##
Of course this is for vector addition of V and a*t, but i could draw no other conclusions from this
I have drawn it multiple times, I am not trying to solve the problem in my head. Even the book has a detailed picture
Here is one I found on the web, just to show that i know what you are saying
http://2.bp.blogspot.com/-lLb0RcwG_LQ/UKpPDbIYQ-I/AAAAAAAAB3s/Yklf-9iXLQ8/s1600/scan00014.jpg
Please...
I assume that for dt time they don't change their direction and move in straight line.
$$\text{Initial slope}=\sqrt{3}$$
$$\text{Slope after }dt=m _2$$
$$d\theta= \tan^{-1}
\left(\frac
{l*\frac sqrt{3} 2 -dl \sqrt{3}} {\frac l 2}}-sqrt{3}\right)$$
It is V^2/r, but i will need radius of...
I made another attempt at it.
I assumed that the triangle that forms between the three, rotates with a constant angular velocity. This too yielded nothing.
This is the working for that https://m.imgur.com/gallery/9X34cs1
I have tried assuming that they move dl distance along the stright line in dt time, ignoring the direction change. Then I used co-ordinate geometry to find the new slope and calculate d(theta). I was left with a value that had terms of dl and dt, and hence useless
Homework Statement
Three particles A, B, C, are situated at the vertices of equilateral triangle of side l. They approach each other with velocity v, such that A always moves toward B, B towards C and C towards A. What will be the initial acceleration?
Homework EquationsThe Attempt at a...