So far I got:
e^z = 1
I know e^z = e^x (cos y + i Sin y)
Then,
e^x cos y = 1
e^x sin y = 0
I know that for sin y = 0, y = 2 pi * K, where k is an integer.
After this step I'm stuck!
The second problem: e^z = 1 + i...
The problem states:
Find the Radius of Convergence of the following Power Series:
(a) ∑ as n goes from zero to infinity of Z^n!
(b) ∑ as N goes from zero to infinity of (n + 2^n)Z^n
For (a) I think the radius of convergence is 1 but I'm a bit unsure of that...
Great
The problem states:
Find the Radius of Convergence of the following Power Series:
(a) Sumation as n goes from zero to infinity of Z^n!
(b) Sumation as N goes from zero to infinity of (n + 2^n)Z^n
For (a) I think the radius of convergence is 1 but I'm a bit unsure of that...