yf^2 + sin(xy) = f
I get:
y2f∂f/∂x +f^2∂y/∂x + cos(xy)*(x∂y/∂x+y) = ∂f/∂x
y2f∂f/∂x +f^2∂y/∂x + x∂y/∂xcos(xy) + ycos(xy) = ∂f/∂x
∂y/∂x[f^2 + cos(xy)] + ycos(xy) + y2f∂f/∂x = ∂f/∂x
I have no idea how to remove the ∂f/∂x on the left hand side :/
Homework Statement
Calculate ∂f/∂x and ∂f/∂y for the following function:
yf^2 + sin(xy) = f
The Attempt at a Solution
I understand basic partial differentiation, but I have no idea how to approach the f incorporation on both sides of the equation nor what you would explicitly call this...