So the electric field will stay the same? For the equation energy density = (1/2)εE^2, what changes then?
Yeah, I think it's a better approach. In what situations should I use finding the stored energy and dividing the volume rather than (1/2)εE^2, and vice versa? Thanks.
I am confused about how the electric field changes in this problem - is E' = E/Ke=E/2? Is E = V/d a correct usage?
When I solve it this way, the answer is incorrect:
change in energy density = (1/2)ε(E'2- E2) = (1/2)ε(E2/4 - E2) = (1/2)ε(-3/4)(V/2d)2.
What am I doing wrong? Thanks.