I am sorry, but yes there is a little mistake, the function that defines the surface is:
f(x, y, z) = -x2 + sin(y) - 2z2 = 0
I missed the minus sign before x2
f(x, y, z) = x2 + sin(y) - 2z2 = 0 defines a surface in 3 dimensions. First I need to find the equation of the normal line to the surface at point P0(2pi, 0, 3/2). Then, I need to find the point which is at a distance of 4 from the tangent plane at the point P0
Equation for the normal line at...