Recent content by rabiakhan.91

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    How Long Until the Drink Reaches Room Temperature?

    Homework Statement A person walks into a bar and orders a drink made of 1.5oz of rum, 4 oz of coke, and 3oz of ice. How long does it take the drink to reach the room temperature of 22 degC Homework Equations q=mcΔT q =mL where L is the latent heat of fusion ΔQ/Δt=k(Tf-Ti)/L The...
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    Linear motion converted into rotatory motion problem

    you have no idea how thankful i am of u! u have helped me in return of no personal gain! i am literally moved by your act of kindness! thank you so so much! hope all your problems(physics and otherwise :P) work out ! :)
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    Linear motion converted into rotatory motion problem

    since momentum is conserved, collision before the moemntum is = after collision mvinitial = (m+M)v we rearrange for v so v= m vinitial/ (m+M) then energy is conserved after the collision so 1/2 (m+M) v^2 = (m+M)g(L-Lcosθ) then we replace v after collision with initial velocity so we...
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    Linear motion converted into rotatory motion problem

    o yes yes! sorry! so the energy equation after substituting for v will be [ (m+M) m^2 * vinitial ^2 ] /2(m+M) = (m + M)g (L-Lcostheta) and then vinitial = [2g(m+M)^2 (L-Lcos theta)] ^1/2 / m
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    Linear motion converted into rotatory motion problem

    so momentum is mvinitial = (m+M)v and after rearranging it will be v= mvinitial/(m+M) then energy is conserved after collision 1/2(m+M)v^2 = mg(L-Lcosθ) then we will substitute the value of v from the conservation of momentum equation so it will be 1/2 *mvinitial^2/(m+M) = g(L-Lcosθ) and...
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    Linear motion converted into rotatory motion problem

    umm but then how will we find the equations? K.E before the collision is 1/2mvinitial^2 after the collision = 1/2(m+M)v^2 + mg(L-Lcostheta) momentum is conserved so mvinitial = (m+M)v
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    Linear motion converted into rotatory motion problem

    ok so i got the height as L-Lcostheta the kinetic energy of the block is 0 and the kinetic energy of both of them at the heighest point is 0. so 1/2mv(initial)^2 = (m+M)g(L-Lcostheta) then i just rearranged to find v i am still a little doubtful about the height though
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    Linear motion converted into rotatory motion problem

    i got the answer v = (2g(m+M)(L-Lcostheta)/m)^1/2 what do u think?
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    How Do You Calculate the Final Velocity of Two Colliding Cars?

    Homework Statement Two cars, both of mass m, collide and stick together. Prior to the collision, one car had been traveling north at speed 2v, while the second was traveling at speed v at an angle phi south of east. After the collision, the two-car system travels at speed v_final at an angle...
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    Linear motion converted into rotatory motion problem

    that was helpful! but while finding the potential energy, how will we find the height?
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    Linear motion converted into rotatory motion problem

    Homework Statement In a ballistic pendulum an object of mass m is fired with an initial speed v_0 at a pendulum bob. The bob has a mass M, which is suspended by a rod of length L and negligible mass. After the collision, the pendulum and object stick together and swing to a maximum angular...
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