Pedestrian A rolled into a gutter after being struck by an automobile.
Pedestrian B came along, looked down at Pedestrian A and asked, "Say there, have an accident?"
Pedestrian A replied, "No, thanks, just had one!"
Since a person can't toss a pebble at a speed higher than about a hundred miles/hour, the pebble will be traveling about 900 miles/hour in the direction of the train's travel relative to the ground. If it takes the pebble a half a second to fall to the ground, the pebble will hit the ground over...
Thank you for addressing the question. However, your answer doesn't help me. No matter what the mass of the object, the object will accelerate at a rate of (about) 32 ft/sec2 if dropped in a vacuum (to remove the effect of air resistance on very low density objects) .
If f = ma, and in the...
Great, something concrete to discuss!
If the marking on the bottle signifies 1.5 lbm, and I want to accelerate that bottle at 20 ft/sec2, then applying f=ma, I would have to apply a force of 30 lb-ft/sec2 ? :
1.5 lb X 20 ft/sec2 = 30 lb-ft/sec2
In the old physics classes I had, the...
It is very frustrating to not be able to get past what is "correct". I know what is correct. Even in the dark ages we learned what was called "canceling terms" or what you refer to as "dimensional analysis". What I am trying to get help with is dealing with what is "incorrect" and learning how...
Then why do all calculations for acceleration, energy, and so forth made using pounds require that the pounds be divided by the acceleration due to gravity?
Now I am confused, again! Are you telling me that 10 pounds of potatoes have a mass of 10 lbm? I thought I would have to divide the 10 pounds by 32+ to approximate the mass in lbm.
Apparently, we exist in a paradigm (the "everyday world') wherein pounds and kilograms are assumed to refer to "weight". Numbers are given units of "lb" or "kg" without distinction. Why that is so is irrelevant to the practical problem solver. It may be incorrect terminology, but we seem to be...
How would I know that?
I see that. I used a poor example, obscuring my intent. I should have stated a problem that asked something like:
How much force would be required to accelerate 1kg at a rate of 3 m/sec^2
Thank you for trying to help me understand. If you will, please try to clarify the following dilemma for me:
I am asked how much force is required to accelerate 1kg to 30m/s. Do I assume the 1kg to be mass or to be weight? The calculation will be different, depending on which is used, right...