Homework Statement
I have this 4x4 determinant and usually these are just mechanical work, until I stumbled upon one containing x, how should one go about solving these type of determinants?
[x 2x 4 x ]
[1 2 2x 1 ]
[2x x-1 2 3x]
[ 2 x+1 x+3 x-1]
What are the different values of...
This is neither homework nor independent study, it was a brain teaser( or so you could call it) I found.
A new mathematical operation has been implemented , call it #
It is used within our knowledge of numbers( it operates with all sets of numbers) and works together with our known operations (...
Here's a slight brainteaser for you all ! Seems simple at sight but can be harder than you think :D P.S I'm working on it as of now, it's an interesting question.
Solve :
1/(√x+√(x+2))+1/(√x+√(x-2))=1/4
Thanks for the quick replies ! Really appreciate it !
I was thinking along the lines of having a number n which would be that exact value but as I worked it through I got stuck, where you presented the n = 30^2 + 30a + b part was where I got stuck, but your explanation was really good so thanks...
I stumbled upon a math question, at the glance of it, seemed easy.
One is supposed to find the exact value of this square root:
√30*31*32*33+1
They are all under the square root operator and Fundamental BEDMAS/BIDMAS applies of course.
The trick here is when the condition states that one...
Problem : Two hikers, Call them Carl and David started to walk at 12pm (noon) along the same path but in opposite directions. Let's assume Carl walked from Point A to point B and David did the opposite, walked from Point B to Point A. Both of them have different constant speed. They pass each...
Wnc ( Work done by non-conservative forces) = 0
Therefore : PEi + KEi = PEf + KEf
point A through point B
PEa + KEa = PEb + KEb
KEa = 0 because it’s at rest and PEb is also 0 because it reaches the lowest point of travel
thus, PEa = KEb
h = L because it is attached by the string with length...
Well, yeah :)
The thing is now , people have gotten an answer that the speed at point D is sqrt of 4g(y-L) or it might be sqrt of 4g(L-y)
However, I get it to be sqrt of 2gy