Recent content by projjal

I think that's not correct.

Yeah. You also know the potential at centre due to charge q and wid that you get the answer.

Hint:the whole sphere is an equipotential region.

Everything's OK.

Why that?

Well, sorry for my incomprehensibility.Its first time I came across such problem.

Without θ question is incomplete. The horizontal force applied is 20N : only this information cannot determine the mass of the rope.

Yes, the mean PE will be half of the maximum , but not just like that. PE at any instant is 1/2 kx2 = 1/2kx02cos2(ωt+ø) , avg. of cos2(ωt+ø) over a time period is 1/2.

How can you just cut the ln sign from both sides?

Thats where you made the mistake.The beam passing through the plexi covers larger optical path. So its path would be 1/2λ greater than the other.

In the torque equation, there'll be torque due to the force of friction.

man you made a slight arithmetic mistake in the last line.

Correct.Now find the current through C & D (or A & B) and hence you will get the current through the connecting wire.

No. It would mean (A parallel C) in series with (B parallel D). Calculate the current through the resistors and from this you can find the current through the bridge.

What if E vector is discontinuous at one point?