let's say i had 115% for my online homework which is worth 16% of the final grade and 4% for my written homework which is worth 8% of the final grade. how would i find my total percent for both online+hw together? I am thinking (115/2 + 115 + 2)/2 = 87.25% for both written homework and online...
a car starts from rest and acclerates down a straight track of length L= 1600m with a constant accleration. If the time it takes for the car to travel the final d= 100 m of the track (from 1500m to 1600m) is T=0.125s, then the acceleration of the car is... the answer is 80.7 m/s^2
this isn't...
i don't think i modeled it incorrectly, because there's a similar problem in the book, but maybe i made a mistake so who knows, but here are the first few terms...
10 - 1000x^2 + 10000x^4 -10000000x^6 + 1000000000x^8...
coefficients of the odd powers are zero...
but i can't seem to get...
the function f(x) = \frac{10}{1+100*x^2}
is represented as a power series
f(x) = \sum_{n=0}^{\infty} C_nX^n
Find the first few coefficients in the power series:
C_0 = ____
C_1 = ____
C_2 = ____
C_3 = ____
C_4 = ____
well f(x) = \frac{10}{1+100*x^2} can be written as...
well the 4th term is \frac{(0.3)^6}/{6!} but it comes out to .000001
and the 5th term has 8 zeros, so the 4th term is closer to the value 0.0000001. so is that how the book got 4th term as an answer?
\sum_{n=1}^{\infty} a_n = 1 - \frac {(0.3)^2}{2!} + \frac {(0.3)^4}{4!} - \frac {(0.3)^6}{6!} + \frac {(0.3)^8}{8!} - ...
how many terms do you have to go for your approximation (your partial sum) to be within 0.0000001 from the convergent value of that series?
the answer to this...
Each of the following statements is an attempt to show that a given series is convergent or divergent using the Comparison Test (NOT the Limit Comparison Test.) For each statement, enter C (for "correct") if the argument is valid, or enter I (for "incorrect") if any part of the argument is...
Test each of the following series for convergence by either the Comparison Test or the Limit Comparison Test.
\sum_{n=1}^\infty \frac{2n^4}{n^5+7} this diverges using the p-series and comparison test right? p <1
\sum_{n=1}^\infty \frac{2n^4}{n^9+7} and this converges right? because p >...
let's say i had 90% on my exams, worth a total of 30%. Also, on homework i have a total of 85% which is worth a total of 40%. i want to know what i need to get on the final if the final is worth 30% of my grades? 90% is an A in the class.
(.30)*(.90) + (.40)*(.85) + x = .90
i thought it...
Determine whether the sequence a_n = \frac{1^2}{n^3} + \frac{2^2}{n^3} + ... + \frac{n^2}{n^3} converges or diverges. If it converges, find the limit.
wouldnt it converge to 0?
Find the limit of the sequence whose terms are given by a_n = (n^2)(1-cos(5.2/n))
well as n->inf, cos goes to 1 right? so shouldn't the limit of this sequence be 0?