Recent content by priscilla98

\int \frac{1}{\3sqrt[]{x}^{2}

It's the third root.

\int \frac{1}{3\sqrt[]{x}^{2}} This is the integral, thanks a lot

I'm sorry. The problem states to evaluate the given integral which is 1 / 3√x^2 dx

Please any help is appreciated. Am i right so far?

Homework Statement Evaluate the given integral:: ∫1/∛(x^2 ) dx The Attempt at a Solution ∫(x^2)^-1/3 (1) dx 1/2 ∫(x^2)^-1/3 (2) dx But somehow I'm stuck here. I know this is an easy problem but I just can't figure it out. Any help is appreciated. Thanks a lot

Homework Statement Using the following vapor pressure data solve for the heat of vaporization for substance x. T VP 20 100 30 175 40 325 Homework Equations ln (P1/P2) = -Heat of vap/RT (1/T2 - 1/T1) The Attempt at a Solution I know the answer is...

Okay, then we don't know the length of this poster yet. The area of the poster is 300 sq. in. I know the formula is A = l x w. Knowing that we know the area of the poster, can't we use this to find the dimensions of the poster. The width of the margins is 2 by 1 inches, right?

Okay, that's true. Wouldn't you change the length and width of the poster from inches to square inches? I know the length of this poster is 2 inches and the width is 1 inch. Therefore, wouldn't the length be 20 inches and the width is 10 inches

Homework Statement A rectangular poster is to be made out of cardboard. The margins on the top and the bottom will be 2 inches. The margins on the sides will be 1 inch. the are of the poster devoted to the printed material must be 300 square inches. (a) To the nearest .001 inches, find...

Homework Statement Anybody know any good websites or notes for review for the AP Cal AB or BC exam? I know sparknotes have some good notes as well as course notes. - Thanks

By using dy/dx for y = x^-3 + x, would it be this below dy d d --- = --- (x^-3) + --- (x) dx dx dx

I'm getting the m from the problem. It states as my first post is y = x^-3 + x. Now, find y^m. I have even given the multiple choices for this question. You're right, you can' really help me if I don't understand it. Okay, now you state that first the mth derivative was the second now it's a...

That would probably be it. So, now it be would be y = (x^-3 + x)^3, right?

I really do appreciate the help, thanks. It's just that I'm really confused on this equation.