Thanks! That's what I reckon too, so I set up the equation using P1 as 241,2kPa and P2 being 186kPa.
Ended up getting a height (h2) of 3 meters (rounded)..
Hi! Did you mean that the velocity can or can't change since the flowmass must be constant?
But would it be correct to say that P1; is the new pressure on the pressure gauge (3) = 241,2kPa?
And P2 being what I calculated in task 3?
Hi, everyone! Doing some fluid flow/Bernoulli tasks.
Ok, so the task is:
«A hose with a radius of 0,035m is connected to a nozzle, which reduces the radius of the hose to 0,018m (2). The hose carries (qv) 0,0075 m3/sec and the totalpressure (3) in the wide section (1) is 211 kPA. The density of...
Yes, I got 6.098 and rounded it up to 6,1kg. But the process is correct?
What is the real difference between Q1 and Q4?
With Q1 being: Heat of fusion water * mass of ice = 334400 * x = 334400J
And Q4: Specific heat capacity for ice* m * ∆T=> 2097*x*12 = 25164J
Because isn't both of these the...
Do I need to make a Q4, for the process when the ice goes from 0-12°C? Using Specific heat capacity for ice* m * ∆T=> 2097*12 = 25164J
Then in the end, add together Q1+Q2+Q4 / Q3(The heat lost)
Q1 334400 +Q2 229900 + Q4 25164 = 589464J
Q3 = 3594800J
3594800J/589464J = 6,01 kg
Am I getting...
I just can't seem to get the correct result.. what numbers did you get? I bet it would be easier using a computer yes, I just really want to learn how to do it on paper before using a computer. :smile:
So ok, the ice goes from -12, freezing, and into melting at 0°C..
For Q1, I then used the...
Hello!
I'm having some problems solving a task..
"Ice with temperature -12°C is used to cool down water from 98°C. to 55°C. . Specific heat capacity for ice = 2097J/kgK, Secific heat capacity water: 4180 j/kgK. Heat of fusion for water is 334,4kJ7K. The mass of the water is 20kg."
∆T water =...