I don't quite think i understand this.
As i see it,
for k = -1
1st term = -1 + 1 = 0
2nd term = -1+1/-1+1 = undefined
3rd term = undefined
4th term undefined
This happens since the bottom part is always -1 + 1 = 0 and you can't divide by 0.
What you guys are saying is...
well the sequence for the first 10 terms goes like this
1/2, 3/2, 5/3, 8/5, 13/8, 21/13, 34/21, 55/35, 89/55, 144/89
from what i can tell these number are converging towards a number and since the numerator is always greater than the denominator, the number they are converging towards...
Hello, I was not sure if this belonged in the precalculus or calculus section so i hope no one minds that i posted it here.
This is a problem that has completely lost me.
http://img76.imageshack.us/img76/9191/continuousfractionrg3.gif
T1 = 1 + 1
T1 = 1+ (1/1+1)
T3 = 1+...
Hey,
Does anyone know a good program (similar to word) that can be used to write mathematical formulas? It kind of sucks to write them in word as it is very limited.
Lol preferably a freeware.
Now that you put it this way, I figured out that sin A = 2/10 = 11.5 degrees. Since F = 500 x cos 11.5
F = 490 N approximately
F = ma
490 = 5000 x a
490/5000 = a
a = 0.098 m/seconds squared
This look correct?
Damn this was easy!
I think the question is complicated and therefore hard to understand. What is the use of saying that the point the rope is connected to is 2m away from the bank or that the rope is 10m long. WHY EVEN MENTION A CANAL?
well, thank you. This was quite simple :D
Can anyone help me with this question? I would appreciate it.
A horse pulls a barge of mass 5000 kg along a canal using a rope 10 m long. The rope is attached to a point on the barge 2m from the bank. As the barge starts to move, the tension in the rope is 500 N. Calculate the barge's initial...