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    How Do Absolute Values Affect Solving Function Equations?

    Homework Statement I do not see how the two equations in each example are related, what should I do with them? (the l's are absolute value brackets): a) Let g(x) = 3x - 3 + l x+5 l. Find all values of a which satisfy the equation: g(a) = 2a +8 b) Let h(x) = l x l - 3x...
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    Imposing Coordinates Homework: Eriks & Ferrys Positions & Distances

    Homework Statement Eriks disabled boat is floating at a stationary location 3 miles East and 2 miles North of Kingston. A ferry leaves Kingston heading due East towards Edmonds at 12mph. Erik leaves the sailboat in a dingy heading due South at 10ft/sec (hoping to intercept the ferry)...
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    Max Accel & Force for Mass Block & Cart

    Homework Statement A block of mass mblock = 1.5 kg rests on a cart of mass mcart = 3.5 kg, which moves without friction on a horizontal surface. The coefficient of static friction between the block and the cart is µ = 0.7. The cart is accelerating to the right. a) What is the maximum...
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    Blocks on Floor - Tension between blocks

    Thanks for all the help everyone! After a few more calculations and substitutions I finally got the answer of 10N.
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    Blocks on Floor - Tension between blocks

    The other force would be the pulling force on both blocks. I am unsure about what to do with this. My book gives: F-T=m1a and T=m2a m1 and m2 seem to be backwards in this problem as the rope is connected between m1 and m2 [m2]------[m1]----- F=force (net force? 4.12) T=tension...
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    Blocks on Floor - Tension between blocks

    Thanks Tiny Tim! Maybe I have been staring at physics too long today 'cause I'm sure this is more obvious than it seems to me right now. So a=2.06, m=2 (the back block) which equals 4.12N. a does not equal 9.8 because this is the horizontal. It makes sense to me that the above...
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    Blocks on Floor - Tension between blocks

    Homework Statement A block of mass m1 = 2 kg and a block of mass m2 = 3 kg are tied together and are pulled from rest across the floor by a force of Fp = 25 N. The coefficient of friction of the blocks with the floor is µ = 0.3. a) What is the acceleration of the two blocks? Answer...
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    What Are The Acceleration and Tension in This Block System?

    Blocks on Floor - I got it! Homework Statement A block of mass m1 = 2 kg and a block of mass m2 = 3 kg are tied together and are pulled from rest across the floor by a force of Fp = 25 N. The coefficient of friction of the blocks with the floor is µ = 0.3. (the blocks are being moved in the...
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    Tennis Ball Drop II: Find Force Exerted on Floor

    So the average speed at which the ball is moiving is the average rate. To calculate this I need to divide the distance by time. My attempt at finding time is: t = sqrt 2s/a s = 5.6 a = 9.81 the answer is t = 1.14 I then take this quantitiy to use: d/t = r d = 5.6 t =...
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    Tennis Ball Drop II: Find Force Exerted on Floor

    Homework Statement A 0.5 kg tennis ball is dropped from rest at a height of 5.6 m onto a hard floor. A flash photograph shows that the ball is compressed a maximum of 0.6 cm when it strikes the floor. b) Assuming that the acceleration of the ball is constant during its contact with the...
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    Solve Tennis Ball Drop: 0.5kg at 5.6m Height

    Thank you very much! These are the little mistakes I continually make and it is VERY helpful having a forum like this to help me get it all straight :redface: You rock!
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    Solve Tennis Ball Drop: 0.5kg at 5.6m Height

    Ok, I understand better what I did with the variables, I had the right numbers but not in the right places! After calculating using: a = 9.81 u = 0 s = 5.6 v= ? I get 2(9.81)(5.6) = 109.872 but this is not the final answer, I am unsure where to take this from here but I think it has...
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    Solve Tennis Ball Drop: 0.5kg at 5.6m Height

    Homework Statement A 0.5 kg tennis ball is dropped from rest at a height of 5.6 m onto a hard floor. Homework Equations a) What is the speed of the ball at the instant of contact with the floor? v = m/s The Attempt at a Solution I need acceleration and I have attempted using...
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    Calculate Force Exerted by Wood on Bullet

    Thanks for the help! I got the correct answer of 388.08 N by taking the equation v^2=u^2 + 2as and solving for a and then multiplying by mass. Both of your suggestions were very helpful in helping me to understand these concepts better! :smile:
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    Calculate Force Exerted by Wood on Bullet

    Homework Statement A bullet of mass 0.0022 kg initially moving at 504 m/s embeds itself in a large fixed piece of wood and travels 0.72 m before coming to rest. Assume that the acceleration of the bullet is constant. What force is exerted by the wood on the bullet? F=N Homework...
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