Homework Statement
A 1.5 kg ball is tied to a string that is .75 m long and whirled in a verticle circle.
A) Find the tension in the string at the top of the circle
B) Find the tension in the string at the bottom of the circle
Homework Equations
Fc=mac
ac= v2/r
The Attempt at a Solution
A)...
Actually could you solve it so that:
a= v2/r
20= v2/8e6
v2= 160,000,000
v= 12,649.1 m/s
GM/r= v2
(6.67e-11)(M)/8e6 = 12649.12
6.67e-11M= 1.28e15
M = 1.92e25
GM/r = v2
(6.67e-11)(1.92e25)/(8e6+300,000)= v2
154293975.9 = v2
12421.5 m/s = v
Was this what you were getting at? I was staring at...
I suppose you mean the F = GMm/r2 equation? My teacher doesn't really teach so it's mostly us students trying to guess at things. So it would become:
GM/r = v2 leaving me with (6.67e-11)(M)/(8e6+300,000) = v2?
I'm sorry thank you for your patience
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So if it is then 5.33 g/cm for the constant then when the weights are said to be less, the spring constant would decrease? Because 40 g/7.5 cm becoming 7g/7.5 cm would be a whole lot less.
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