Recent content by phys194

My bad, the expression in the middle should have been $$A\cos(x)=\frac{-\mu_0H_0}{\sqrt{2} k \sinh(kh_2/2)}.$$ So, the last expression should change accordingly, but the general idea stays the same.

It's a purely magnetostatic problem, so the extra term in Ampère's law can be ignored. This is such a tough problem, I have been working on it for almost three days and I still can't make any sense out of it.

Updates: after a better analysis of the symmetry of the problem (transformations x-> -x, y-> -y leave everything intact), I was able to find that X(x)=Acos(kx)+Bsin(kx) and Y(y) = Ce^(ky)+De^(-ky) OR Ecosh(ky)+Fsinh(ky). The symmetry of the problem implies that no odd terms can appear in the...

Consider the static field configuration shown in the image. There are three layers: 0 = vacuum, 1 = magneto-optic fluid and 2 = covering shell. Each of these layers have their own permittivity and permeability (ε_i,μ_i) (isotrope). A uniform electric field H_0 = H_0/sqrt(2) * (e_x + e_y) is...