Recent content by PerilousGourd

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    I When should one eigenvector be split into two (same span)?

    Are you sure? The highlighted wording in the question makes me think otherwise.
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    I When should one eigenvector be split into two (same span)?

    This question was inspired by 3c) on https://people.phys.ethz.ch/~muellrom/qm1_2012/Solutions4.pdf Given the operator \hat{B} = \left(\matrix{b&0&0\\0&0&-ib\\0&ib&0}\right) I find correctly that the eigenvalues are \lambda = b, \pm b. To find the eigenvectors for b, I do the following...
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    I Mathematics of tensor products in the Bell states

    Thank you for your reply! No reason to, or it actually can't be done? If it can be done, I'd love to see the process, as it would help with my intuition a lot. How can you tell when \otimes should be interpreted as a tensor product to be expanded and when it should be interpreted another way...
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    I Mathematics of tensor products in the Bell states

    I'm having trouble with the mathematics of tensor products as applied to Bell states. Say I have the state \begin{align*} \left|\psi\right> &= \frac{1}{\sqrt{2}} \left(\left|0\right>_A \otimes \left|0\right>_B + \left|1\right>_A \otimes \left|1\right>_B\right) \end{align*} How would the...
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    ##\bar{\psi}=e^{i\theta}\psi## global gauge transformation

    Why is ##\bar{\psi}=e^{i\theta}\psi##, where ##\theta## is a real number, used as the global gauge transformation? Why ##e^{i \theta}##; what's the physical significance or benefit? Why is ##\bar{\psi} = e^{i \theta(x)} \psi## the local gauge transformation? What does ##\theta## being a...
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