I know WS cell only contains one lattice point, so we would have to trace bisectors, and obtain some kind of irregular shape.
Anyways, I wanted to check if what I did is okay. It is considering a fictitious point as the center of the (non-primitive) unit cell, which would be one of those...
First of all, thank you all for your responses, they are giving me a lot of insight in this issue.
So, as I can observe, the phenomenon is mainly due to the materials and the little capacitances the current finds on its way.
I have thought about hypotetical physical phenomena: magnetic...
Thank you all, now I can imagine better how this phenomenon works.
Is there a way to estimate the currents and power consumption when the circuit is open?
I have plot the circuit the best I could. The cable is 10 m long, and the two insulated wires have each one a section of 1.5 mm•mm.
Let's suppose there is no capacitance.
Changing the position of the bulbs is indifferent.
But it's a circuit I have made, with a long cable and a battery. The effect of dimly lighting after being switched OFF happens. Both for bulb and LED. I don't know why.
The bulb/LED is connected to a long cable consisting of two insulated wires.
I want to know how is this phenomenon happening in a physical way. I mean, not referring to the quality of used materials.
I suppose that for the bulb, it happens kinda Joule effect, and when the circuit becomes...
Ah okay, I think that speed (or kinetic energy) is to look when studying stopping power. We see that matter absorbs and scatters alpha particles that traverse it.
I can also see that Fig.4 is the gradient of Fig.3 , and recognise the shape of the functions.
The key on this is that stopping...
We would have the Fig.3 as a decreasing line function and Fig.4 as a constant value.
But how do we know from Fig 3 or 4 that it is velocity and not other parameter what creates dependence for dE/dx ?
ah okay, so it is because at equal displacements (the markers on abscissa), the plotted function starts kinda lineally, but then decays steeply. As a result, energy decreases steeply -> the squared velocity decreases steeply -> the stopping power increases, isn't it?
Thanks!
We can read: "The velocity dependence of the stopping power, increasing with decreasing velocity, is obvious from Fig.4".
I know why the stopping power depends on velocity as Bethe equation states, but I do not know how I can observe that dependence on a Bragg curve.