u know, i have done the above proof, i.e,
curl of (A χ B)
but it came out to be (B .\nabla)A-B(\nabla . A)-(A.\nabla) B+ A (\nabla . B)
u see, i am just a beginner in this topic, and i didn't do it like u did it. instead i broke it down all the way and did it. I know it is stupid but i was...
@MarcAlexande
you told that u have done derivatives and functions. then we can define an integral as simply anti-derivative or primitive of a function f(x).that is,a function ∅(x) is called an integral of a function f(x) if ∅'(x) = f(x).
for eg:- x^4/4 is a primitive of x^3, because d/dx(...
will these successive tangent curves touch the function f(x) curve at some nth order of the derivative or will they tend to touch but will actually never touch the f(x) curve?
the above series is Taylor series, isn't it?
you mean derivatives depend on this series? Like when the order is 2, we have 2 terms from taylor's series. When it is of order 3, we have 3 terms of taylor series and likewise?
We recently had a lecture on black holes in the college. We were told about the new development going on in the field of theoretical physics on black holes. The prof. was telling that most of the singularities have been removed 2 a great extent but introducing another different set of...
Hi everybody, I have a question:
We know that the geometrical representation of 1st order derivative is the slope of a function. Then what is the geometrical representation of derivatives having order more than 1? I mean what does it actually represent in a function? Please some body clear my...