Homework Statement
We have to measure emf of a battery. We have to voltmeters. Each of them when connected alone across the battery, they read V1 = 0.9V and V2 = 0.6V and when both of them are connected to the battery simultaneously, they both read V3 = 0.45V . What is the emf of...
Why don't wires in any circuit touch each other and get short circuited?
If two current carrying wires carry charges in same direction then from ampere's law,can't they touch each other due to attractive forces?
The tension will be - (mg/L)*x where x is the distance from the bottom
Elongation...it should be the force causing the elongation ...in this case the weight so it is (W/AY)dx where dx is the length of the segment
Yep.It's the weight of the bar...I kinda mixed the wire from the first case
In the second case,some stress will be acting because the width gets elongated...I have heard that young's modulus makes sense when stress and strain are proportional.
In the second case,the wire is acting along the...
In the second case,the wire gets elongated but the restoring force that is tension remains constant but it;'s width get elongated so will stress also act in that case?
Makes sense then.So the uppermost point is most probable to break first
So the strain will not tell us the condition for breaking but the stress will,right?
If the breaking stress is equal to the external force (weight) at the topmost point then beyond this the wire breaks,right?What does...
Since at the top,the maximum tension acting on is the weight of the wire mg (Why are we calculating this for the upprmost point tho)If at breaking stress,it has to elongate before it breaks then can we use the formulae of strain here maybe
Since the stress is magnitude of the internal restoring force per unit which in this case is the tension then it will be greatest at the top
How exactly did you know to apply the formulae for strain in the second case...I struggled a lot for that
My definitions prior to solving a question for...