Recent content by Pakbabydoll

o when I say fungal form of growth I mean when we grow it over night in TSB first there is very low count and 2nd it looks fungal in strings and all, and I put it on BA to check for hemolysis but it looked like yeast on BA. I also got a positive for MSA and MYP agars.

Well this bacteria is a little different. Its def a bacteria but it exhibits fungal form of growth. Its an endophyte so a lot is not known about them specially since our sample is from somewhere very unusual. I got the permission to use another lab and I extracted the DNA Friday, I am planning...

As far as I know API is used only for gram negative rods, mine is a gram positive cocci. So I can't use API. We had to find unknowns in our microbiology class but we were given a list of 20 some bacteria so I had a strategy. Here there is no list, I don't have any information except that its a...

ok so I work in a chemistry lab but I am a microbiology major. Our lab works with endophytes. We have a positive result for one of them and I have to identify this thing by April. This task seems impossible to me. They did not keep track of where this sample came from or even which organism it...

so so for future users this is how you get the answer: (1/2)(9.8)(m)^2+(1/4)(9.8)(m)^2 than take square root of that but I still don't know why you get it that way... its too late for me to plug it into the system so I am not sure if its even right but that's how you get it...

HEEEEEELPPPPPPPPPPPPPPPPPP please!

Homework Statement n my homework we are asked to find the magnitude of the reaction force at the pivot at a instant and earlier in the problem we found the magnitude of the angular speed at one instant, the magnitude of the angular acceleration at the same instant, and the magnitude of the...

So to get the normal force on an incline can I use the angle? Would it be like 9.8*cos(21)*2? and how do you get friction for a specific area?

Homework Statement A spring with a spring- constant 3.4N/ cm is compressed 29cm and released. The 2 kg mass skids down the frictional incline of height 50 cm and inclined at 21 degrees angle. The acceleration of gravity is 9.8 m/s^2. The path is frictionless except for a distance of .07 m...

ok so there is: Friction between top and bottom block Friction between bottom block and the tile Normal force but would not that just cancel with gravity? Tension in + and - X^ directions (since all the motion is in the X^ ) Oh and I can't turn that problem in anymore it was due this morning...

That was my solution for that problem! I am stuck at that point

so any help guys?

yes sir I am going to attach the hwk file. it is problem #15

wrong again... sorry... ok so I was wondering since its a pully should not we multiply the bottom acceleration by 2. umm so the bottom block would be moving twice as fast as the top block? am I making any sense? o and I have one try left to plug in the answer so can someone do this for me...

So this is what I have its probably completely wrong because I did it this way and a graduate physics student did it another way but both of our answers are wrong. N-(M1+M2)g (2.29+ 5.65)9.8 77.812(.18)= 14.006 (2.29)(9.8)(.18)= 4.03956 F-(f1+f2)=ma F-(14.006+4.03956)=7.94(2) F=33.92576...