Recent content by oyster21

Can anyone please say if he got this write?

i confused myself.. thanks for your earlier input though. :smile:

so the total distance traveled would be: 100m+400m+265.3m=765.3m

stage 3: Deceleration from 40/ms at 3m/s2 Distance travelled S=ut+1/2at2 S=40x13.3-0.5x(3)(13.3)2=265.3 is that rite for stage 3?

Is you graph correct as it stayed at 40m/s for 10seconds

Stage 1: Acceleration from rest to 40m/s. Distance travelled S=ut+1/2at2 S=0x5+0.5(8)(5)2=100m Travelled at 40m/s over 10seconds Distance travelled S=ut+1/2at2 S=40x10+0.5(0)(10)2=400m stage 3: Deceleration from 40/ms at 3m/s2 Distance travelled S=ut+1/2at2 S=40x13.3+0.5x(3)(13.3)2=797.3...

i've used the same equations for each stage. ( s=ut+½at2) 1st stage distance = 100m 2nd stage distance= 797.3m 3rd stage distance = 400m 100m+797.3m+400m = 1297.3m ?

would i use the same equation to work out each stage seperatley?

u = 0 t = 28.3sec (combined time of all 3 stages) a = 8 s = ? S= ut+½at2 = 0 + ½ (8)(28.3)2 = 3,203.56m (total distance travelled) is this correct?

Ok My answer to the 1st question is the acceleration is 8m/s2 my answer to the 2nd question is time taken to come to rest is 13.3seconds how would I work out the 3rd question? also can you tell me if my answers so far are correct? thank you for your patience though.

A vehicle of a mass 1000kg performs 3 stages of motion which are: 1)Accelerates uniformly from rest to a velocity of 40m/s in 5 seconds. 2)Continues at this velocity for 10 seconds 3)decelerates uniformly at a rate of 3m/s2 Question: 1) find the acceleration in the1st stage? 2)the time...

1): a=(V-U)/t a=(40m/s - 0m/s) /5sec = 8m/s2 2): U-V/t > t= V/a t= 0m/s - 40m/s / -3m/s2 = 13.3sec 3): 8m/s2 = 8x8= 64m 64m x 10sec = 640m How do I work out the total distance traveled over the 3 stages with the information if its correct for question 3? and do I have to take into...

So it should be 12.75m/s2 correct?

V2= U2+2as rearranged as: a= (V2 - U2) /2s 20km/h = 20,000m 200km/h = 200,000m 2x120m = 240m 20,000m / 3600sec = 5.6m/s 200,000m / 3600sec =55.6m/s a= 55.6m/s2 - 5.6m/s2 / 240m = 12.75m/s Please can anyone tell me if my answer is correct?

20,000m / 3600sec = 5.6m/s 200,000m/3600sec = 55.6m/s 55.6 - 5.6 = 50m/s