Theory says that in real life in band 118 - 136 MHz we would use 8,33 kHz spacing in civil aviation and 25 kHz spacing in military aviation. However, I think this problem is just made up to see if I can use Dopplers formula... However, if I focus only on Doppler part of this problem, the shift...
God... thank you.. quite tired this afternoon...
f=f0*((v+v0)/v)
where f = ?
f0 = 118 000 000 Hz
v´ = speed of light = 299 000 000 ms
v0 = speed of airplane towards the tower = 2 MACH = 636 ms
f = 118 000 270.7 Hz
it means that the singal will be shifted by 270.7 Hz.. so all we need is to...
allright, thanks!
So if I use a common formula for doppler and set original frequency to 118 MHz, the frequency which tower (or other plane) got is 354 MHz
f=f0*((v+v0)/v)
where f = ?
f0 = 118 MHz
v´ = speed of sound = 343 ms
v0 = speed of airplane towards the tower = 2 MACH = 636 ms
I got the...
I found it confusing since there is only "mutual" speed of both aircrafts and hence I do not know how to correctly put it into the common Dopplers formula...